24^2=((3x-1)*(x+3))/2

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Solution for 24^2=((3x-1)*(x+3))/2 equation: 


x in (-oo:+oo)

24^2 = ((3*x-1)*(x+3))/2 // - ((3*x-1)*(x+3))/2

24^2-(((3*x-1)*(x+3))/2) = 0

(-1*(3*x-1)*(x+3))/2+576 = 0

(-1*(3*x-1)*(x+3))/2+(2*576)/2 = 0

2*576-1*(3*x-1)*(x+3) = 0

1155-3*x^2-8*x = 0

1155-3*x^2-8*x = 0

1155-3*x^2-8*x = 0

DELTA = (-8)^2-(-3*4*1155)

DELTA = 13924

DELTA > 0

x = (13924^(1/2)+8)/(-3*2) or x = (8-13924^(1/2))/(-3*2)

x = -21 or x = 55/3

(x+21)*(x-55/3) = 0

((x+21)*(x-55/3))/2 = 0

((x+21)*(x-55/3))/2 = 0 // * 2

(x+21)*(x-55/3) = 0

( x+21 )

x+21 = 0 // - 21

x = -21

( x-55/3 )

x-55/3 = 0 // + 55/3

x = 55/3

x in { -21, 55/3 }

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